6a^2-25a-25=0

Solution for 6a^2-25a-25=0 equation:

6a^2-25a-25=0

a = 6; b = -25; c = -25;
Δ = b2-4ac
Δ = -252-4·6·(-25)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-35}{2*6}=\frac{-10}{12}
=-5/6
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+35}{2*6}=\frac{60}{12}
=5
$